What is (\partial)/(\partial x)(3x+2ysin(x)) ?

The answer to (\partial)/(\partial x)(3x+2ysin(x)) is 3+2ycos(x)

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(\partial)/(\partial x)(3x+2ysin(x))

\frac{\partial}{\partial x} (3 x + 2 y sin (x))

3 + 2 y cos (x)

Solution steps

\frac{\partial}{\partial x} (3 x + 2 y sin (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (2 y sin (x))

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (2 y sin (x)) = 2 y cos (x)

= 3 + 2 y cos (x)

\frac{d}{d x} (6^{x} lo g_{3} (x))

y = (6 x^{2} - 10 x + 1)^{- 4}

\int [\frac{( sin ( x ) )}{x}] d x

\frac{d}{d x} (3 + 4.1 cos (0.9 x))

\frac{d y}{d x} + x y = 4 x

What is (\partial)/(\partial x)(3x+2ysin(x)) ?
The answer to (\partial)/(\partial x)(3x+2ysin(x)) is 3+2ycos(x)