What is the derivative of 3+4.1cos(0.9x) ?

The derivative of 3+4.1cos(0.9x) is -3.69sin(0.9x)

What is the first derivative of 3+4.1cos(0.9x) ?

The first derivative of 3+4.1cos(0.9x) is -3.69sin(0.9x)

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\frac{d}{d x} (3 + 4.1 cos (0.9 x))

- 3.69 sin (0.9 x)

Solution steps

\frac{d}{d x} (3 + 4.1 cos (0.9 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (4.1 cos (0.9 x))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (4.1 cos (0.9 x)) = - 3.69 sin (0.9 x)

= 0 - 3.69 sin (0.9 x)

Simplify

= - 3.69 sin (0.9 x)

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y = (9 x)^{3 x}

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What is the derivative of 3+4.1cos(0.9x) ?
The derivative of 3+4.1cos(0.9x) is -3.69sin(0.9x)
What is the first derivative of 3+4.1cos(0.9x) ?
The first derivative of 3+4.1cos(0.9x) is -3.69sin(0.9x)