What is the tangent of f(x)=sqrt(7x+4),\at x=3 ?

The tangent of f(x)=sqrt(7x+4),\at x=3 is y= 7/10 x+29/10

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tangent of f(x)=sqrt(7x+4),\at x=3

tangent of

f (x) = 7 x + 4, at x = 3

y = \frac{7}{10} x + \frac{29}{10}

Solution steps

Find the tangent point:

(3, 5)

Find the slope of

f (x) = 7 x + 4 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 4}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(3, 5) : y = \frac{7}{10} x + \frac{29}{10}

y = \frac{7}{10} x + \frac{29}{10}

\frac{d}{d x} (\frac{x ^{5} + 9}{x ^{3}})

\int \frac{1}{( x ^{2} + a ^{2} )} d x

\frac{d}{d x} ((\frac{4}{5} x)^{5})

y = sin (x), y = cos (x), x = 0, x = 2 π

\frac{d}{d x} (e^{x^{6}} + lo g_{5} (π))

What is the tangent of f(x)=sqrt(7x+4),\at x=3 ?
The tangent of f(x)=sqrt(7x+4),\at x=3 is y= 7/10 x+29/10