What is area y=sin(x),y=cos(x),x=0,x=2pi ?

The answer to area y=sin(x),y=cos(x),x=0,x=2pi is 4sqrt(2)

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area y=sin(x),y=cos(x),x=0,x=2pi

area

y = sin (x), y = cos (x), x = 0, x = 2 π

42

Decimal

5.65685 \dots

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{0}^{2 π} ∣ sin (x) - cos (x) ∣ d x : 42

The area is:

= 42

\frac{d}{d x} (e^{x^{6}} + lo g_{5} (π))

\frac{\partial}{\partial x} (2 x + 3 y - 6)

(9 - x^{3})^{- 2}

\frac{d}{d x} (\frac{1}{4} x^{4} - 2 x^{3} + \frac{9}{2} x^{2} + 1)

\int_{0}^{3} \frac{1}{x ^{2} + 3} d x

What is area y=sin(x),y=cos(x),x=0,x=2pi ?
The answer to area y=sin(x),y=cos(x),x=0,x=2pi is 4sqrt(2)