What is the derivative of f(x)= 4/(3x^2) ?

The derivative of f(x)= 4/(3x^2) is -8/(3x^3)

What is the first derivative of f(x)= 4/(3x^2) ?

The first derivative of f(x)= 4/(3x^2) is -8/(3x^3)

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derivative of

f (x) = \frac{4}{3 x ^{2}}

- \frac{8}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{4}{3 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{3} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{3} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{3} (- 2 x^{- 2 - 1})

Simplify

\frac{4}{3} (- 2 x^{- 2 - 1}) : - \frac{8}{3 x ^{3}}

= - \frac{8}{3 x ^{3}}

\int \frac{x ^{2} e ^{x}}{( x + 2 ) ^{2}} d x

\int - \frac{18}{x ^{19}} d x

\frac{d x}{d t} - \frac{x}{t - 1} = t^{2} + 2

x \to 0 lim (\frac{( 1 + x ) ^{2} - 1}{x})

y^{^{'}} = 1 + 9 x - 5 y

What is the derivative of f(x)= 4/(3x^2) ?
The derivative of f(x)= 4/(3x^2) is -8/(3x^3)
What is the first derivative of f(x)= 4/(3x^2) ?
The first derivative of f(x)= 4/(3x^2) is -8/(3x^3)