What is the integral of-(18)/(x^{19)} ?

The integral of-(18)/(x^{19)} is 1/(x^{18)}+C

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integral of-(18)/(x^{19)}

\int - \frac{18}{x ^{19}} d x

\frac{1}{x ^{18}} + C

Solution steps

\int - \frac{18}{x ^{19}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 18 \cdot \int \frac{1}{x ^{19}} d x

Apply the Power Rule

: - \frac{1}{18 x ^{18}}

= - 18 (- \frac{1}{18 x ^{18}})

Simplify

- 18 (- \frac{1}{18 x ^{18}}) : \frac{1}{x ^{18}}

= \frac{1}{x ^{18}}

Add a constant to the solution

= \frac{1}{x ^{18}} + C

\frac{d x}{d t} - \frac{x}{t - 1} = t^{2} + 2

x \to 0 lim (\frac{( 1 + x ) ^{2} - 1}{x})

y^{^{'}} = 1 + 9 x - 5 y

\int \frac{cos ( x )}{sin ^{4} ( x )} d x

y^{2} = x^{2} (x + 1)

What is the integral of-(18)/(x^{19)} ?
The integral of-(18)/(x^{19)} is 1/(x^{18)}+C