What is implicit y^2=x^2(x+1) ?

The answer to implicit y^2=x^2(x+1) is (dy)/(dx)=(3x^2+2x)/(2y)

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implicit y^2=x^2(x+1)

implicit derivative

y^{2} = x^{2} (x + 1)

\frac{d y}{d x} = \frac{3 x ^{2} + 2 x}{2 y}

Solution steps

y^{2} = x^{2} (x + 1)

Treat

y

y (x)

Differentiate both sides:

2 y \frac{d y}{d x} = 3 x^{2} + 2 x

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{3 x ^{2} + 2 x}{2 y}

\frac{d y}{d x} = \frac{3 x ^{2} + 2 x}{2 y}

\frac{6 x}{x ^{2} + 1}

\frac{\partial}{\partial y} (y e^{x} + sin (y))

- 7 sin (7 x)

n = 1 \sum \infty \frac{n}{( n + 1 )}

\frac{d}{d x} (e^{- x^{2}} - 2 e^{- x^{2}} x^{2})

What is implicit y^2=x^2(x+1) ?
The answer to implicit y^2=x^2(x+1) is (dy)/(dx)=(3x^2+2x)/(2y)