What is the sum from n=1 to infinity of n/((n+1)) ?

The sum from n=1 to infinity of n/((n+1)) is diverges

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sum from n=1 to infinity of n/((n+1))

n = 1 \sum \infty \frac{n}{( n + 1 )}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of n/((n+1)) ?
The sum from n=1 to infinity of n/((n+1)) is diverges