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Popular >

derivative of y(θ)=(sin(θ))/5+c/θ

Solution

derivative of

y (θ) = \frac{sin ( θ )}{5} + \frac{c}{θ}

Solution

\frac{1}{5} cos (θ) - \frac{c}{θ ^{2}}

Solution steps

\frac{d}{d θ} (\frac{sin ( θ )}{5} + \frac{c}{θ})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (\frac{sin ( θ )}{5}) + \frac{d}{d θ} (\frac{c}{θ})

\frac{d}{d θ} (\frac{sin ( θ )}{5}) = \frac{1}{5} cos (θ)

\frac{d}{d θ} (\frac{c}{θ}) = - \frac{c}{θ ^{2}}

= \frac{1}{5} cos (θ) - \frac{c}{θ ^{2}}

Graph

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\frac{d}{d x} (\frac{1}{e ^{x^{2}}})

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Frequently Asked Questions (FAQ)

What is the derivative of y(θ)=(sin(θ))/5+c/θ ?
The derivative of y(θ)=(sin(θ))/5+c/θ is 1/5 cos(θ)-c/(θ^2)
What is the first derivative of y(θ)=(sin(θ))/5+c/θ ?
The first derivative of y(θ)=(sin(θ))/5+c/θ is 1/5 cos(θ)-c/(θ^2)