What is the solution for x^2((dy)/(dx))-2xy=3y^4 ?

The solution for x^2((dy)/(dx))-2xy=3y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}

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x^2((dy)/(dx))-2xy=3y^4

x^{2} (\frac{d y}{d x}) - 2 x y = 3 y^{4}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

Solution steps

x^{2} (\frac{d y}{d x}) - 2 x y = 3 y^{4}

Solve Bernoulli ODE:

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

\frac{d}{d x} (3 + x)

\frac{d y}{d x} = 0.6 y

\int e^{x^{3}} \cdot x^{2} d x

\frac{d}{d x} (arctan (sinh (x)))

\frac{d}{d x} ((a x^{2} + b x + c) e^{- \frac{x}{4}})

What is the solution for x^2((dy)/(dx))-2xy=3y^4 ?
The solution for x^2((dy)/(dx))-2xy=3y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}