What is (\partial)/(\partial s)(ln(rs^8t^8)+1) ?

The answer to (\partial)/(\partial s)(ln(rs^8t^8)+1) is 8/s

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(\partial)/(\partial s)(ln(rs^8t^8)+1)

\frac{\partial}{\partial s} (ln (r s^{8} t^{8}) + 1)

\frac{8}{s}

Solution steps

\frac{\partial}{\partial s} (ln (r s^{8} t^{8}) + 1)

Treat

r, t

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial s} (ln (r s^{8} t^{8})) + \frac{\partial}{\partial s} (1)

\frac{\partial}{\partial s} (ln (r s^{8} t^{8})) = \frac{8}{s}

\frac{\partial}{\partial s} (1) = 0

= \frac{8}{s} + 0

Simplify

= \frac{8}{s}

cos (sin (e^{x}))

\int_{1}^{2} \frac{2 x - 1}{x} d x

t (\frac{d y}{d t}) + 5 y = 4 t, y (1) = 2

x^{- \frac{3}{2}}

x \to + 5 lim (x^{2} - 2 x + 1)

What is (\partial)/(\partial s)(ln(rs^8t^8)+1) ?
The answer to (\partial)/(\partial s)(ln(rs^8t^8)+1) is 8/s