What is the limit as z approaches i of z(z+1) ?

The limit as z approaches i of z(z+1) is i(i+1)

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limit as z approaches i of z(z+1)

z \to i lim (z (z + 1))

i (i + 1)

Solution steps

z \to i lim (z (z + 1))

Plug in the value

z = i

= i (i + 1)

f (x) = ln (4 x + 1)

\frac{d}{d x} (\frac{1}{ln ^{2} ( x )})

\int \frac{1}{x 9 x ^{2} + 16} d x

\int t^{2} t^{3} + 1 d t

\int \frac{r ^{3}}{4 + r ^{2}} d r

What is the limit as z approaches i of z(z+1) ?
The limit as z approaches i of z(z+1) is i(i+1)