What is the derivative of x^2+5x-8 ?

The derivative of x^2+5x-8 is 2x+5

What is the first derivative of x^2+5x-8 ?

The first derivative of x^2+5x-8 is 2x+5

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\frac{d}{d x} (x^{2} + 5 x - 8)

2 x + 5

Solution steps

\frac{d}{d x} (x^{2} + 5 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (8) = 0

= 2 x + 5 - 0

Simplify

= 2 x + 5

- 18 y^{^{''}} - 14 y^{^{'}} = 0, y (3) = - 3, y^{^{'}} (3) = - 3

\int \frac{3 x}{x ^{2} - 11} d x

\int \frac{4 x e ^{x} + e ^{4 x}}{e ^{3 x}} d x

\int_{1}^{4} f (x) d x

\frac{d}{d x} (x (x^{5} + 1)^{3})

What is the derivative of x^2+5x-8 ?
The derivative of x^2+5x-8 is 2x+5
What is the first derivative of x^2+5x-8 ?
The first derivative of x^2+5x-8 is 2x+5