What is integral from 1 to 4 of f(x) ?

The answer to integral from 1 to 4 of f(x) is (15f)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of f(x)

\int_{1}^{4} f (x) d x

\frac{15 f}{2}

Solution steps

\int_{1}^{4} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{4}

= f [\frac{x ^{2}}{2}]_{1}^{4}

Compute the boundaries:

\frac{15}{2}

= f \frac{15}{2}

Simplify

= \frac{15 f}{2}

\frac{d}{d x} (x (x^{5} + 1)^{3})

\frac{\partial}{\partial y} (x e^{y} - ln (x))

- x - \frac{1}{x}

x \to 0 lim (x^{- 1})

\int_{- 2}^{3} \frac{14}{x ^{4}} d x

What is integral from 1 to 4 of f(x) ?
The answer to integral from 1 to 4 of f(x) is (15f)/2