What is the derivative of x+1/(x+2) ?

The derivative of x+1/(x+2) is 1-1/((x+2)^2)

What is the first derivative of x+1/(x+2) ?

The first derivative of x+1/(x+2) is 1-1/((x+2)^2)

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\frac{d}{d x} (x + \frac{1}{x + 2})

1 - \frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{1}{x + 2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{1}{x + 2})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x + 2}) = - \frac{1}{( x + 2 ) ^{2}}

= 1 - \frac{1}{( x + 2 ) ^{2}}

f (x) = x (x + 3)

\frac{d}{d x} (6 - 3 x)

y^{^{'}} = 3 y + 7, y (0) = 4

t^{2} + 2

\int 7 x e^{4 x} d x

What is the derivative of x+1/(x+2) ?
The derivative of x+1/(x+2) is 1-1/((x+2)^2)
What is the first derivative of x+1/(x+2) ?
The first derivative of x+1/(x+2) is 1-1/((x+2)^2)