What is the solution for (x^2+y^2)dx-2xydy=0 ?

The solution for (x^2+y^2)dx-2xydy=0 is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}

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(x^2+y^2)dx-2xydy=0

(x^{2} + y^{2}) d x - 2 x y d y = 0

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

Solution steps

(x^{2} + y^{2}) d x - 2 x y d y = 0

Solve Bernoulli ODE:

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

1 - ln (3 x)

f (x) = 3 x^{2}, at x = 1

\frac{d}{d x} (x (4 x + 1)^{\frac{1}{3}})

\int \frac{t}{t - 2} d t

\int \frac{1}{x - c} d x

What is the solution for (x^2+y^2)dx-2xydy=0 ?
The solution for (x^2+y^2)dx-2xydy=0 is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}