What is the derivative of 1.394(1.006^x) ?

The derivative of 1.394(1.006^x) is 0.00833…*1.006^x

What is the first derivative of 1.394(1.006^x) ?

The first derivative of 1.394(1.006^x) is 0.00833…*1.006^x

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\frac{d}{d x} (1.394 (1.006)^{x})

0.00833 \dots \cdot 1.00 6^{x}

Solution steps

\frac{d}{d x} (1.394 (1.006)^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.394 \frac{d}{d x} (1.00 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 1.394 \cdot 1.00 6^{x} ln (1.006)

Simplify

1.394 \cdot 1.00 6^{x} ln (1.006) : 0.00833 \dots \cdot 1.00 6^{x}

= 0.00833 \dots \cdot 1.00 6^{x}

\int \frac{1}{( x ^{2} - 196 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (arccot (4 x))

\frac{d}{d x} (y^{2} (2 - x) - x^{3})

x^{2} + 2

y^{^{'}} + 3 y = 0, y (0) = 0

What is the derivative of 1.394(1.006^x) ?
The derivative of 1.394(1.006^x) is 0.00833…*1.006^x
What is the first derivative of 1.394(1.006^x) ?
The first derivative of 1.394(1.006^x) is 0.00833…*1.006^x