What is the first derivative of x^2+2 ?

The first derivative of x^2+2 is 2x

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derivative of x^2+2

derivative of

x^{2} + 2

2 x

Solution steps

\frac{d}{d x} (x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= 2 x + 0

Simplify

= 2 x

y^{^{'}} + 3 y = 0, y (0) = 0

\frac{\partial}{\partial x} (e^{(y + 1) x})

f (x) = \frac{x ^{3} + 9 x ^{2} + x - 8}{x}

\frac{\partial}{\partial x} (4 a x)

\frac{d}{d x} ((x^{2} + 6)^{9})