What is the solution for 2x^2y^{''}+3xy^'=y ?

The solution for 2x^2y^{''}+3xy^'=y is y=c_{1}sqrt(x)+(c_{2})/x

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2x^2y^{''}+3xy^'=y

2 x^{2} y^{^{''}} + 3 x y^{^{'}} = y

y = c_{1} x + \frac{c _{2}}{x}

Solution steps

2 x^{2} y^{''} (x) + 3 x y^{'} (x) = y

Solve linear ODE:

y = c_{1} x + \frac{c _{2}}{x}

y = c_{1} x + \frac{c _{2}}{x}

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What is the solution for 2x^2y^{''}+3xy^'=y ?
The solution for 2x^2y^{''}+3xy^'=y is y=c_{1}sqrt(x)+(c_{2})/x