What is the derivative of (x^3)/8 ?

The derivative of (x^3)/8 is (3x^2)/8

What is the first derivative of (x^3)/8 ?

The first derivative of (x^3)/8 is (3x^2)/8

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derivative of

\frac{x ^{3}}{8}

\frac{3 x ^{2}}{8}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{8} \cdot 3 x^{3 - 1} : \frac{3 x ^{2}}{8}

= \frac{3 x ^{2}}{8}

\int cos^{4} (6 x) d x

\frac{d}{d x} (\frac{1}{e} e^{x})

\frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2}

\int x^{2} \cdot sin (x^{3}) d x

n = 1 \sum \infty 15 (\frac{1}{100})^{n}

What is the derivative of (x^3)/8 ?
The derivative of (x^3)/8 is (3x^2)/8
What is the first derivative of (x^3)/8 ?
The first derivative of (x^3)/8 is (3x^2)/8