What is (\partial)/(\partial x)(xy+x) ?

The answer to (\partial)/(\partial x)(xy+x) is y+1

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(\partial)/(\partial x)(xy+x)

\frac{\partial}{\partial x} (x y + x)

y + 1

Solution steps

\frac{\partial}{\partial x} (x y + x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

= y + 1

\frac{d}{d x} (- 2 sin (x) + 2 sin (2 x))

\int (cos (x) - sec (x)) d x

(t + 5)^{\frac{2}{3}} (3 t^{2} - 2)^{3}

\frac{d y}{d x} + 5 y = 70, y (1) = 110

x \to 10 lim (\frac{7 x ^{2} - 70 x}{x ^{2} - 100})

What is (\partial)/(\partial x)(xy+x) ?
The answer to (\partial)/(\partial x)(xy+x) is y+1