What is the derivative of 3x^2-e^x ?

The derivative of 3x^2-e^x is 6x-e^x

What is the first derivative of 3x^2-e^x ?

The first derivative of 3x^2-e^x is 6x-e^x

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\frac{d}{d x} (3 x^{2} - e^{x})

6 x - e^{x}

Solution steps

\frac{d}{d x} (3 x^{2} - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (e^{x}) = e^{x}

= 6 x - e^{x}

\int 4^{t} sin (4^{t}) d t

\frac{d}{d x} (y - x + 1 + x - y + 1)

f (x) = ln (x + 9)

- 4 ln (+ \frac{1}{x} - 4)

(x^{2} + 2 y^{2}) d x = x y d y

What is the derivative of 3x^2-e^x ?
The derivative of 3x^2-e^x is 6x-e^x
What is the first derivative of 3x^2-e^x ?
The first derivative of 3x^2-e^x is 6x-e^x