What is taylor (2x)/(sqrt(e^{2x^2)-1)} ?

The answer to taylor (2x)/(sqrt(e^{2x^2)-1)} is

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taylor (2x)/(sqrt(e^{2x^2)-1)}

taylor

\frac{2 x}{e ^{2 x^{2}} - 1}

\frac{2}{e ^{2} - 1} + \frac{2 ( - e ^{2} - 1 )}{( e ^{2} - 1 ) e ^{2} - 1} (x - 1) - \frac{4 e ^{4} - 28 e ^{2}}{2 ( e ^{2} - 1 ) ^{\frac{5}{2}}} (x - 1)^{2} - \frac{- 20 e ^{6} + 88 e ^{4} + 172 e ^{2}}{6 ( e ^{2} - 1 ) ^{\frac{7}{2}}} (x - 1)^{3} - \frac{8 e ^{8} + 288 e ^{6} - 2520 e ^{4} - 1136 e ^{2}}{24 ( e ^{2} - 1 ) ^{\frac{9}{2}}} (x - 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

= \frac{2}{e ^{2} - 1} + \frac{\frac{d}{d x} ( \frac{2 x}{e ^{2 x^{2}} - 1} ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{2 x}{e ^{2 x^{2}} - 1} ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{2 x}{e ^{2 x^{2}} - 1} ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= \frac{2}{e ^{2} - 1} + \frac{\frac{2 ( - e ^{2} - 1 )}{( e ^{2} - 1 ) e ^{2} - 1}}{1 !} (x - 1) + \frac{- \frac{4 e ^{4} - 28 e ^{2}}{( e ^{2} - 1 ) ^{\frac{5}{2}}}}{2 !} (x - 1)^{2} + \frac{- \frac{- 20 e ^{6} + 88 e ^{4} + 172 e ^{2}}{( e ^{2} - 1 ) ^{\frac{7}{2}}}}{3 !} (x - 1)^{3} + \frac{- \frac{8 e ^{8} + 288 e ^{6} - 2520 e ^{4} - 1136 e ^{2}}{( e ^{2} - 1 ) ^{\frac{9}{2}}}}{4 !} (x - 1)^{4} + \dots

Refine

= \frac{2}{e ^{2} - 1} + \frac{2 ( - e ^{2} - 1 )}{( e ^{2} - 1 ) e ^{2} - 1} (x - 1) - \frac{4 e ^{4} - 28 e ^{2}}{2 ( e ^{2} - 1 ) ^{\frac{5}{2}}} (x - 1)^{2} - \frac{- 20 e ^{6} + 88 e ^{4} + 172 e ^{2}}{6 ( e ^{2} - 1 ) ^{\frac{7}{2}}} (x - 1)^{3} - \frac{8 e ^{8} + 288 e ^{6} - 2520 e ^{4} - 1136 e ^{2}}{24 ( e ^{2} - 1 ) ^{\frac{9}{2}}} (x - 1)^{4} + \dots

\frac{d}{d x} (23 sin (x) + 2 cos (x))

\int_{1}^{2} 3 d x

(x^{2} + y^{2})^{2} = 4 x^{2} y, (- 1, 1)

x \to 0 lim (\frac{x + 2}{x})

\int e^{x} (2 x - 2) d x

What is taylor (2x)/(sqrt(e^{2x^2)-1)} ?
The answer to taylor (2x)/(sqrt(e^{2x^2)-1)} is