What is the derivative of y=arccot(x) ?

The derivative of y=arccot(x) is -1/(x^2+1)

What is the first derivative of y=arccot(x) ?

The first derivative of y=arccot(x) is -1/(x^2+1)

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derivative of

y = arccot (x)

- \frac{1}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (arccot (x))

Apply the common derivative:

\frac{d}{d x} (arccot (x)) = - \frac{1}{x ^{2} + 1}

= - \frac{1}{x ^{2} + 1}

\int_{0}^{6} \frac{36}{x ^{2} + 36} d x

\frac{d}{d x} (\frac{2 ^{x}}{ln ( 2 )})

(2, 3), (1, 3)

n = 6 \sum \infty n^{2} - 16

2 x + y = 4, y = x, y = 0

What is the derivative of y=arccot(x) ?
The derivative of y=arccot(x) is -1/(x^2+1)
What is the first derivative of y=arccot(x) ?
The first derivative of y=arccot(x) is -1/(x^2+1)