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Popular >

y^{''}-2y^'+y=1

Solution

y^{^{''}} - 2 y^{^{'}} + y = 1

Solution

y = c_{1} e^{t} + c_{2} t e^{t} + 1

Solution steps

y^{''} (t) - 2 y^{'} (t) + y = 1

Solve linear ODE:

y = c_{1} e^{t} + c_{2} t e^{t} + 1

y = c_{1} e^{t} + c_{2} t e^{t} + 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-2y^'+y=1 ?
The solution for y^{''}-2y^'+y=1 is y=c_{1}e^t+c_{2}te^t+1