What is the sum from n=0 to infinity of e^{4n} ?

The sum from n=0 to infinity of e^{4n} is diverges

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sum from n=0 to infinity of e^{4n}

n = 0 \sum \infty e^{4 n}

diverges

Solution steps

n = 0 \sum \infty e^{4 n}

Apply Series Ratio Test:

diverges

= diverges

\int_{2}^{- 1} 3^{x} d x

n = 2 \sum \infty \frac{1}{n ^{\frac{3}{2}}}

\int \frac{( x ^{2} )}{( ( x - 1 ) ( x ^{2} + 2 x + 1 ) )} d x

\frac{d}{d x} (\frac{1}{cos ( x )})

\frac{s + 1}{( s + 2 ) ( s + 3 )}

What is the sum from n=0 to infinity of e^{4n} ?
The sum from n=0 to infinity of e^{4n} is diverges