What is the sum from n=2 to infinity of 1/(n^{3/2)} ?

The sum from n=2 to infinity of 1/(n^{3/2)} is converges

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sum from n=2 to infinity of 1/(n^{3/2)}

n = 2 \sum \infty \frac{1}{n ^{\frac{3}{2}}}

converges

Solution steps

n = 2 \sum \infty \frac{1}{n ^{\frac{3}{2}}}

Apply p-Series Test:

converges

= converges

\int \frac{( x ^{2} )}{( ( x - 1 ) ( x ^{2} + 2 x + 1 ) )} d x

\frac{d}{d x} (\frac{1}{cos ( x )})

\frac{s + 1}{( s + 2 ) ( s + 3 )}

x \to 0 + lim (ln (\frac{7}{x ^{2}}))

n = 1 \sum \infty (\frac{3}{8})^{1 - n}

What is the sum from n=2 to infinity of 1/(n^{3/2)} ?
The sum from n=2 to infinity of 1/(n^{3/2)} is converges