What is the sum from n=1 to infinity of (n-1)/(5n-1) ?

The sum from n=1 to infinity of (n-1)/(5n-1) is diverges

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sum from n=1 to infinity of (n-1)/(5n-1)

n = 1 \sum \infty \frac{n - 1}{5 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 1}{5 n - 1}

Apply Series Divergence Test:

diverges

= diverges

(x^{2} + 2 y^{^{'}}) y^{^{''}} + 2 x y^{^{'}} = 0

\frac{d}{d x} (\frac{3 + 8 x}{5 - 6 x})

\int (\frac{4}{x}) d x

x \to 1 + lim ((ln (x))^{x - 1})

\frac{d}{d x} (8 x^{3} - 108 x^{2} + 480 x)

What is the sum from n=1 to infinity of (n-1)/(5n-1) ?
The sum from n=1 to infinity of (n-1)/(5n-1) is diverges