What is the derivative of 8x^3-108x^2+480x ?

The derivative of 8x^3-108x^2+480x is 24x^2-216x+480

What is the first derivative of 8x^3-108x^2+480x ?

The first derivative of 8x^3-108x^2+480x is 24x^2-216x+480

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\frac{d}{d x} (8 x^{3} - 108 x^{2} + 480 x)

24 x^{2} - 216 x + 480

Solution steps

\frac{d}{d x} (8 x^{3} - 108 x^{2} + 480 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{3}) - \frac{d}{d x} (108 x^{2}) + \frac{d}{d x} (480 x)

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (108 x^{2}) = 216 x

\frac{d}{d x} (480 x) = 480

= 24 x^{2} - 216 x + 480

x \to 0 lim ((0.5)^{x})

y^{'} = y^{2}

\int \frac{x ( x - 1 )}{1 - x 2 - x} d x

\int yz d x

cos (e^{t a n (2 x)})

What is the derivative of 8x^3-108x^2+480x ?
The derivative of 8x^3-108x^2+480x is 24x^2-216x+480
What is the first derivative of 8x^3-108x^2+480x ?
The first derivative of 8x^3-108x^2+480x is 24x^2-216x+480