What is (\partial}{\partial x}(\frac{2x-y)/2) ?

The answer to (\partial}{\partial x}(\frac{2x-y)/2) is 1

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(\partial}{\partial x}(\frac{2x-y)/2)

\frac{\partial}{\partial x} (\frac{2 x - y}{2})

1

Solution steps

\frac{\partial}{\partial x} (\frac{2 x - y}{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial x} (2 x - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (y))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y) = 0

= \frac{1}{2} (2 - 0)

Simplify

\frac{1}{2} (2 - 0) : 1

= 1

x^{^{''}} + (x^{^{'}})^{2} = 0

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What is (\partial}{\partial x}(\frac{2x-y)/2) ?
The answer to (\partial}{\partial x}(\frac{2x-y)/2) is 1