What is the derivative of (x^3/(x^2-1)) ?

The derivative of (x^3/(x^2-1)) is (x^4-3x^2)/((x^2-1)^2)

What is the first derivative of (x^3/(x^2-1)) ?

The first derivative of (x^3/(x^2-1)) is (x^4-3x^2)/((x^2-1)^2)

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\frac{d}{d x} (\frac{x ^{3}}{x ^{2} - 1})

\frac{x ^{4} - 3 x ^{2}}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{x ^{2} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} ) ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) x ^{3}}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2} - 1) = 2 x

= \frac{3 x ^{2} ( x ^{2} - 1 ) - 2 x x ^{3}}{( x ^{2} - 1 ) ^{2}}

Simplify

\frac{3 x ^{2} ( x ^{2} - 1 ) - 2 x x ^{3}}{( x ^{2} - 1 ) ^{2}} : \frac{x ^{4} - 3 x ^{2}}{( x ^{2} - 1 ) ^{2}}

= \frac{x ^{4} - 3 x ^{2}}{( x ^{2} - 1 ) ^{2}}

\int arctan (2 t) d t

x \to + 4 lim (3)

y^{^{''}} - 3 y^{^{'}} + 4 y = 0

\frac{d}{d x} (\frac{( 4 x - 2 ) ^{4}}{3 x ^{2} + 7})

\frac{d}{d x} (x^{2} + 2 x - 1)

What is the derivative of (x^3/(x^2-1)) ?
The derivative of (x^3/(x^2-1)) is (x^4-3x^2)/((x^2-1)^2)
What is the first derivative of (x^3/(x^2-1)) ?
The first derivative of (x^3/(x^2-1)) is (x^4-3x^2)/((x^2-1)^2)