What is the derivative of sqrt(x^2+2x-1) ?

The derivative of sqrt(x^2+2x-1) is (x+1)/(sqrt(x^2+2x-1))

What is the first derivative of sqrt(x^2+2x-1) ?

The first derivative of sqrt(x^2+2x-1) is (x+1)/(sqrt(x^2+2x-1))

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Popular >

\frac{d}{d x} (x^{2} + 2 x - 1)

\frac{x + 1}{x ^{2} + 2 x - 1}

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 1)

Apply the chain rule:

\frac{1}{2 x ^{2} + 2 x - 1} \frac{d}{d x} (x^{2} + 2 x - 1)

= \frac{1}{2 x ^{2} + 2 x - 1} \frac{d}{d x} (x^{2} + 2 x - 1)

\frac{d}{d x} (x^{2} + 2 x - 1) = 2 x + 2

= \frac{1}{2 x ^{2} + 2 x - 1} (2 x + 2)

Simplify

\frac{1}{2 x ^{2} + 2 x - 1} (2 x + 2) : \frac{x + 1}{x ^{2} + 2 x - 1}

= \frac{x + 1}{x ^{2} + 2 x - 1}

x y^{^{'}} = y + (x y)^{\frac{1}{2}}

\frac{d y}{d x} + y = 10

\int_{1}^{4} (x) d x

\frac{d ^{3}}{d x ^{3}} (e^{x} cos (x))

\int 9 (ln (x))^{2} d x

What is the derivative of sqrt(x^2+2x-1) ?
The derivative of sqrt(x^2+2x-1) is (x+1)/(sqrt(x^2+2x-1))
What is the first derivative of sqrt(x^2+2x-1) ?
The first derivative of sqrt(x^2+2x-1) is (x+1)/(sqrt(x^2+2x-1))