What is the derivative of 3sqrt(x)-4x^3+2^x-e+7 ?

The derivative of 3sqrt(x)-4x^3+2^x-e+7 is -12x^2+ln(2)*2^x+3/(2sqrt(x))

What is the first derivative of 3sqrt(x)-4x^3+2^x-e+7 ?

The first derivative of 3sqrt(x)-4x^3+2^x-e+7 is -12x^2+ln(2)*2^x+3/(2sqrt(x))

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\frac{d}{d x} (3 x - 4 x^{3} + 2^{x} - e + 7)

- 12 x^{2} + ln (2) \cdot 2^{x} + \frac{3}{2 x}

Solution steps

\frac{d}{d x} (3 x - 4 x^{3} + 2^{x} - e + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (2^{x}) - \frac{d e}{d x} + \frac{d}{d x} (7)

\frac{d}{d x} (3 x) = \frac{3}{2 x}

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d e}{d x} = 0

\frac{d}{d x} (7) = 0

= \frac{3}{2 x} - 12 x^{2} + 2^{x} ln (2) - 0 + 0

Simplify

= - 12 x^{2} + ln (2) \cdot 2^{x} + \frac{3}{2 x}

y = 1 + x^{3}, (2, 3)

\int \frac{1}{( x - 2 ) ln ( x - 2 )} d x

\int (16 x^{3} - 3 x^{2} + 2) d x

x \to 2 lim (\frac{3 x ^{2} + 4 - 4 x ^{2} + 6 x}{x ^{2} - 4})

\int \frac{cos ( x )}{3 + sin ( x )} d x

What is the derivative of 3sqrt(x)-4x^3+2^x-e+7 ?
The derivative of 3sqrt(x)-4x^3+2^x-e+7 is -12x^2+ln(2)*2^x+3/(2sqrt(x))
What is the first derivative of 3sqrt(x)-4x^3+2^x-e+7 ?
The first derivative of 3sqrt(x)-4x^3+2^x-e+7 is -12x^2+ln(2)*2^x+3/(2sqrt(x))