What is the derivative of-4sin^2(x) ?

The derivative of-4sin^2(x) is -4sin(2x)

What is the first derivative of-4sin^2(x) ?

The first derivative of-4sin^2(x) is -4sin(2x)

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\frac{d}{d x} (- 4 sin^{2} (x))

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (- 4 sin^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= - 4 \cdot 2 sin (x) cos (x)

Simplify

- 4 \cdot 2 sin (x) cos (x) : - 4 sin (2 x)

= - 4 sin (2 x)

\int 16 cos^{2} (x) d x

y^{^{''}} - 4 y = \frac{( e ^{2 x} )}{( x )}

x \to - 3 lim (- x^{2} - x + 4)

x \to 0 lim (x 2)

(2 x - 1) ln (2 x - 1)

What is the derivative of-4sin^2(x) ?
The derivative of-4sin^2(x) is -4sin(2x)
What is the first derivative of-4sin^2(x) ?
The first derivative of-4sin^2(x) is -4sin(2x)