What is the limit as x approaches 0 of \sqrt[x]{2} ?

The limit as x approaches 0 of \sqrt[x]{2} is diverges

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limit as x approaches 0 of \sqrt[x]{2}

x \to 0 lim (x 2)

diverges

Solution steps

x \to 0 lim (x 2)

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x 2) = \infty

x \to 0 - lim (x 2) = 0

= diverges

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What is the limit as x approaches 0 of \sqrt[x]{2} ?
The limit as x approaches 0 of \sqrt[x]{2} is diverges