What is derivative of f(x)=cos(sqrt(4t+12)) ?

The answer to derivative of f(x)=cos(sqrt(4t+12)) is (dt)/(dx)=0

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derivative of f(x)=cos(sqrt(4t+12))

derivative of

f (x) = cos (4 t + 12)

\frac{d t}{d x} = 0

Solution steps

f (x) = cos (4 t + 12)

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{sin ( 2 t + 3 ) \frac{d t}{d x}}{t + 3}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

x \to 0 lim (\frac{y ^{1 - x}}{1 - x})

y^{^{''}} - 6 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 1

x \to 5 lim (x^{2} + 4)

\int \frac{3 x ^{2} - 3}{x ^{3} - 3 x} d x

3 x \frac{d y}{d x} + 5 y = 10

What is derivative of f(x)=cos(sqrt(4t+12)) ?
The answer to derivative of f(x)=cos(sqrt(4t+12)) is (dt)/(dx)=0