What is the first derivative of y=2x-4 ?

The first derivative of y=2x-4 is 2

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derivative of y=2x-4

derivative of

y = 2 x - 4

2

Solution steps

\frac{d}{d x} (2 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (4) = 0

= 2 - 0

Simplify

= 2

\frac{d}{d x} (\frac{1}{x ^{2} + 5})

x \to 1 lim (\frac{x ^{5} - 1}{x - 1})

f (x) = x sin (2^{x})

\frac{1}{x} e^{y} tan (y) y^{^{'}} = e^{x + y}

\frac{\partial}{\partial y} (\frac{4 x}{x ^{2} + y ^{2}})