What is (\partial)/(\partial y)((4x)/(x^2+y^2)) ?

The answer to (\partial)/(\partial y)((4x)/(x^2+y^2)) is -(8xy)/((x^2+y^2)^2)

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(\partial)/(\partial y)((4x)/(x^2+y^2))

\frac{\partial}{\partial y} (\frac{4 x}{x ^{2} + y ^{2}})

- \frac{8 x y}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{4 x}{x ^{2} + y ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 x \frac{\partial}{\partial y} (\frac{1}{x ^{2} + y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 x \frac{\partial}{\partial y} ((x^{2} + y^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

= - \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \frac{\partial}{\partial y} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= 4 x (- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \cdot 2 y)

Simplify

4 x (- \frac{1}{( x ^{2} + y ^{2} ) ^{2}} \cdot 2 y) : - \frac{8 x y}{( x ^{2} + y ^{2} ) ^{2}}

= - \frac{8 x y}{( x ^{2} + y ^{2} ) ^{2}}

\int \frac{1}{2} (cos (x))^{2} d x

f (x) = \frac{40}{x}, (1, 40)

\int (\frac{x + 1}{x}) d x

\int \frac{1}{2} x^{5} d x

x \to \frac{π}{2} + lim (2 e^{t a n (x)})

What is (\partial)/(\partial y)((4x)/(x^2+y^2)) ?
The answer to (\partial)/(\partial y)((4x)/(x^2+y^2)) is -(8xy)/((x^2+y^2)^2)