What is the tangent of f(x)=(40)/x ,(1,40) ?

The tangent of f(x)=(40)/x ,(1,40) is y=-40x+80

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tangent of f(x)=(40)/x ,(1,40)

tangent of

f (x) = \frac{40}{x}, (1, 40)

y = - 40 x + 80

Solution steps

Find the slope of

f (x) = \frac{40}{x} : \frac{df ( x )}{d x} = - \frac{40}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 40

Find the line with slope m=

- 40

and passing through

(1, 40) : y = - 40 x + 80

y = - 40 x + 80

\int (\frac{x + 1}{x}) d x

\int \frac{1}{2} x^{5} d x

x \to \frac{π}{2} + lim (2 e^{t a n (x)})

f (x) = 3 x^{4} - 8 x^{2}, (- 1, 5)

\frac{\partial}{\partial x} (- 3 x y ln (x y))

What is the tangent of f(x)=(40)/x ,(1,40) ?
The tangent of f(x)=(40)/x ,(1,40) is y=-40x+80