What is the integral of (cos(x))/(x^2) ?

The integral of (cos(x))/(x^2) is -(cos(x))/x-\Si(x)+C

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integral of (cos(x))/(x^2)

\int \frac{cos ( x )}{x ^{2}} d x

- \frac{cos ( x )}{x} - Si (x) + C

Solution steps

\int \frac{cos ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{cos ( x )}{x} - \int \frac{sin ( x )}{x} d x

= - \frac{cos ( x )}{x} - \int \frac{sin ( x )}{x} d x

\int \frac{sin ( x )}{x} d x = Si (x)

= - \frac{cos ( x )}{x} - Si (x)

Add a constant to the solution

= - \frac{cos ( x )}{x} - Si (x) + C

6^{4 - x^{2}}

\frac{d}{d x} (\frac{2 - 3 x - x ^{2}}{x ^{2} - 4})

\frac{d y}{d x} = 4 e^{3 x - 4 y}

\frac{d}{d x} (\frac{6}{2 ^{x}})

\frac{d}{d x} (\frac{x}{x + 5})

What is the integral of (cos(x))/(x^2) ?
The integral of (cos(x))/(x^2) is -(cos(x))/x-\Si(x)+C