What is the solution for (dy)/(dx)=4e^{3x-4y} ?

The solution for (dy)/(dx)=4e^{3x-4y} is y=(ln(16/3 e^{3x}+c_{1}))/4

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(dy)/(dx)=4e^{3x-4y}

\frac{d y}{d x} = 4 e^{3 x - 4 y}

y = \frac{ln ( \frac{16}{3} e ^{3 x} + c _{1} )}{4}

Solution steps

\frac{d y}{d x} = 4 e^{3 x - 4 y}

Solve separable ODE:

y = \frac{ln ( \frac{16}{3} e ^{3 x} + c _{1} )}{4}

y = \frac{ln ( \frac{16}{3} e ^{3 x} + c _{1} )}{4}

\frac{d}{d x} (\frac{6}{2 ^{x}})

\frac{d}{d x} (\frac{x}{x + 5})

x \frac{d y}{d x} = y (y + 1)

f (x) = \frac{6 x}{x + 2}, (4, 4)

f (x) = - \frac{1}{6} (x^{- 6} + x^{12})

What is the solution for (dy)/(dx)=4e^{3x-4y} ?
The solution for (dy)/(dx)=4e^{3x-4y} is y=(ln(16/3 e^{3x}+c_{1}))/4