What is the tangent of f(x)=(6x)/(x+2),(4,4) ?

The tangent of f(x)=(6x)/(x+2),(4,4) is y= 1/3 x+8/3

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tangent of f(x)=(6x)/(x+2),(4,4)

tangent of

f (x) = \frac{6 x}{x + 2}, (4, 4)

y = \frac{1}{3} x + \frac{8}{3}

Solution steps

Find the slope of

f (x) = \frac{6 x}{x + 2} : \frac{df ( x )}{d x} = \frac{12}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(4, 4) : y = \frac{1}{3} x + \frac{8}{3}

y = \frac{1}{3} x + \frac{8}{3}

f (x) = - \frac{1}{6} (x^{- 6} + x^{12})

\frac{x ^{2} - 36}{x - 6}

y^{^{''}} + y = sin (2 x)

\frac{d}{d x} ((2 x^{2} - 1) + (5 x - 6))

f (x) = 12 x^{2}

What is the tangent of f(x)=(6x)/(x+2),(4,4) ?
The tangent of f(x)=(6x)/(x+2),(4,4) is y= 1/3 x+8/3