What is the limit as x approaches 0 of-2xsin(1/x) ?

The limit as x approaches 0 of-2xsin(1/x) is 0

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limit as x approaches 0 of-2xsin(1/x)

x \to 0 lim (- 2 x sin (\frac{1}{x}))

0

Solution steps

x \to 0 lim (- 2 x sin (\frac{1}{x}))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 2 \cdot x \to 0 lim (x sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= - 2 \cdot 0

Simplify

= 0

\frac{\partial}{\partial y} (x y^{2} - 6 x^{2} - 3 y^{2})

y = (8 x^{3} + 5)^{\frac{3}{2}}

y = e^{x}, y = e^{- 2 x}, x = ln (6)

\frac{d}{d x} (- \frac{1}{x ^{2}} - 1)

\frac{480 x}{( x ^{2} + 5 ) ^{3}}

What is the limit as x approaches 0 of-2xsin(1/x) ?
The limit as x approaches 0 of-2xsin(1/x) is 0