What is the limit as m approaches 4 of (3m^2-8m-16)/(2m^2-9m+4) ?

The limit as m approaches 4 of (3m^2-8m-16)/(2m^2-9m+4) is 16/7

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limit as m approaches 4 of (3m^2-8m-16)/(2m^2-9m+4)

m \to 4 lim (\frac{3 m ^{2} - 8 m - 16}{2 m ^{2} - 9 m + 4})

\frac{16}{7}

Decimal

2.28571 \dots

Solution steps

m \to 4 lim (\frac{3 m ^{2} - 8 m - 16}{2 m ^{2} - 9 m + 4})

Simplify

\frac{3 m ^{2} - 8 m - 16}{2 m ^{2} - 9 m + 4} : \frac{3 m + 4}{2 m - 1}

= m \to 4 lim (\frac{3 m + 4}{2 m - 1})

Plug in the value

m = 4

= \frac{3 \cdot 4 + 4}{2 \cdot 4 - 1}

Simplify

= \frac{16}{7}

\int 8 y - 24 d y

x \to 5 + lim (\frac{- 1}{x ^{2} - 25})

\int 9 θ cos (θ) d θ

x^{2} - 3, 2 x

e^{x} + 3 x e^{x}

What is the limit as m approaches 4 of (3m^2-8m-16)/(2m^2-9m+4) ?
The limit as m approaches 4 of (3m^2-8m-16)/(2m^2-9m+4) is 16/7