What is the derivative of 4/(x+2) ?

The derivative of 4/(x+2) is -4/((x+2)^2)

What is the first derivative of 4/(x+2) ?

The first derivative of 4/(x+2) is -4/((x+2)^2)

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\frac{d}{d x} (\frac{4}{x + 2})

- \frac{4}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= 4 (- \frac{1}{( x + 2 ) ^{2}} \cdot 1)

Simplify

4 (- \frac{1}{( x + 2 ) ^{2}} \cdot 1) : - \frac{4}{( x + 2 ) ^{2}}

= - \frac{4}{( x + 2 ) ^{2}}

\frac{\partial}{\partial x} (4 x^{2} + y^{2})

\int \frac{2 - u}{u ^{2} + 2 u + 3} d u

x \to 4 - lim (2 x - 5)

f (1) = x^{6} + 4 e^{x}

\frac{d}{d x} (4 3 x^{5})

What is the derivative of 4/(x+2) ?
The derivative of 4/(x+2) is -4/((x+2)^2)
What is the first derivative of 4/(x+2) ?
The first derivative of 4/(x+2) is -4/((x+2)^2)