What is the derivative of e^x+e^{xx} ?

The derivative of e^x+e^{xx} is e^x+e^{x^2}*2x

What is the first derivative of e^x+e^{xx} ?

The first derivative of e^x+e^{xx} is e^x+e^{x^2}*2x

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\frac{d}{d x} (e^{x} + e^{xx})

e^{x} + e^{x^{2}} \cdot 2 x

Solution steps

\frac{d}{d x} (e^{x} + e^{xx})

Simplify

e^{x} + e^{xx} : e^{x} + e^{x^{2}}

= \frac{d}{d x} (e^{x} + e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{x^{2}})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= e^{x} + e^{x^{2}} \cdot 2 x

\frac{d}{d x} (0.5 x^{3} + 1.5)

\int k

3 e^{4 t - 5}

\frac{d}{d x} (20 e^{- x})

\frac{d}{d x} (\frac{2 x + x ^{2}}{( 1 + x ) ^{2}})

What is the derivative of e^x+e^{xx} ?
The derivative of e^x+e^{xx} is e^x+e^{x^2}*2x
What is the first derivative of e^x+e^{xx} ?
The first derivative of e^x+e^{xx} is e^x+e^{x^2}*2x