What is the derivative of 0.5x^3+1.5 ?

The derivative of 0.5x^3+1.5 is 1.5x^2

What is the first derivative of 0.5x^3+1.5 ?

The first derivative of 0.5x^3+1.5 is 1.5x^2

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\frac{d}{d x} (0.5 x^{3} + 1.5)

1.5 x^{2}

Solution steps

\frac{d}{d x} (0.5 x^{3} + 1.5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.5 x^{3}) + \frac{d}{d x} (1.5)

\frac{d}{d x} (0.5 x^{3}) = 1.5 x^{2}

\frac{d}{d x} (1.5) = 0

= 1.5 x^{2} + 0

Simplify

= 1.5 x^{2}

\int k

3 e^{4 t - 5}

\frac{d}{d x} (20 e^{- x})

\frac{d}{d x} (\frac{2 x + x ^{2}}{( 1 + x ) ^{2}})

y^{^{'}} + 35 y = 7

What is the derivative of 0.5x^3+1.5 ?
The derivative of 0.5x^3+1.5 is 1.5x^2
What is the first derivative of 0.5x^3+1.5 ?
The first derivative of 0.5x^3+1.5 is 1.5x^2