What is the solution for (dy)/(dx)=(x+y)^2-1 ?

The solution for (dy)/(dx)=(x+y)^2-1 is y=-1/(x+c_{1)}-x

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(dy)/(dx)=(x+y)^2-1

\frac{d y}{d x} = (x + y)^{2} - 1

y = - \frac{1}{x + c _{1}} - x

Solution steps

\frac{d y}{d x} = (x + y)^{2} - 1

Solve using substitution:

y = - \frac{1}{x + c _{1}} - x

y = - \frac{1}{x + c _{1}} - x

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What is the solution for (dy)/(dx)=(x+y)^2-1 ?
The solution for (dy)/(dx)=(x+y)^2-1 is y=-1/(x+c_{1)}-x