What is the sum from n=1 to infinity of (-0.3)^n ?

The sum from n=1 to infinity of (-0.3)^n is converges

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sum from n=1 to infinity of (-0.3)^n

n = 1 \sum \infty (- 0.3)^{n}

converges

Solution steps

n = 1 \sum \infty (- 0.3)^{n}

Apply Series Ratio Test:

converges

= converges

x \to 0 lim (\frac{1}{3} x)

f (x) = 3 x - cos (x), at x = 0

\int (9 x + 5)^{2} d x

f (x) = x^{- 5}

x^{2} - 8 x + 9

What is the sum from n=1 to infinity of (-0.3)^n ?
The sum from n=1 to infinity of (-0.3)^n is converges