What is the limit as x approaches infinity of 1/(log_{2)(x)} ?

The limit as x approaches infinity of 1/(log_{2)(x)} is 0

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limit as x approaches infinity of 1/(log_{2)(x)}

x \to \infty lim (\frac{1}{lo g _{2} ( x )})

0

Solution steps

x \to \infty lim (\frac{1}{lo g _{2} ( x )})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to \infty} ( 1 )}{lim _{x \to \infty} ( lo g _{2} ( x ) )}

x \to \infty lim (1) = 1

x \to \infty lim (lo g_{2} (x)) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\int_{- 1}^{0} \frac{1}{x ^{2}} d x

\frac{4 s e ^{- 4 s}}{2 s ^{2} + 50}

\frac{s + 1}{s ^{2} + s + 1}

\frac{d}{d t} (ln (sec (t) + tan (t)))

y^{^{'}} = y (2 x - 5)

What is the limit as x approaches infinity of 1/(log_{2)(x)} ?
The limit as x approaches infinity of 1/(log_{2)(x)} is 0